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Derivation of Displacement-Velocity Gravity Equations

by Ron Kurtus (revised 22 April 2015)

The basis for the derivations of the displacement-velocity gravity equations starts with the equations t = (v − vi)/g and y = gt2/2 + vit, as determined in the Derivation of Velocity-Time Gravity Equations and Derivation of Displacement-Time Gravity Equations lessons.

Note: Displacement is a vector quantity denoting the change in position in a given direction. Velocity is a vector indicating the rate of change of position in a given direction.

By substituting the time relationship in the displacement equation, you can determine the displacement with respect to velocity. From the derived displacement equation, you can then determine the equation for the velocity when the object reaches a given displacement from the starting point.

The derived equations are affected by the initial velocity of the object. This is important in later applications of the equations.

Questions you may have include:

This lesson will answer those questions. Useful tool: Units Conversion



Basis for displacement-velocity derivations

To determine the displacement from the starting point at a given velocity, start with the equations:

t = (v − vi)/g

(Obtained from Derivation of Velocity-Time Gravity Equations)

and

y = gt2/2 + vit

(Obtained from Derivation of Displacement-Time Gravity Equations)

where

Note: The initial velocity is the velocity at which the object is released after being accelerated from zero velocity. Initial velocity does not occur instantaneously.

By substituting the equation for t in the equation for y, you can get the displacement with respect to velocity. Then by solving that equation for v, you get the velocity with respect to displacement equation.

Displacement-velocity relationship

Displacement-velocity relationship

Derivation of displacement for a given velocity

To derive the displacement equation, you can start with the time equation:

t = (v − vi)/g

Square both sides of the equation:

t2 = (v − vi)2/g2

t2 = (v2 − 2vvi + vi2)/g2

Consider the displacement equation:

y = gt2/2 + vit

Substitute for t2 and t from the above equations:

y = g (v2 − 2vvi + vi2)/2g2 + vi(v − vi)/g

Multiply vi(v − vi)/g by 2/2 and combine like terms:

y = (v2 − 2vvi + vi2)/2g + 2(vvi − vi2)/2g

y = (v2 − 2vvi + vi2 + 2vvi − 2vi2)/2g

The resulting general gravity equation for displacement with respect to velocity is:

y = (v2 − vi2)/2g

Derivation of velocity for a given displacement

To get the velocity for a given displacement, multiply both sides of
y = (v2 − vi2)/2g
by 2g and solve for v:

2gy = (v2 − vi2)

v2 = 2gy + vi2

Take the square root of both sides of the equation to get the general gravity equation for velocity with respect to displacement:

v = ±√(2gy + vi2)

where

Summary

The gravity equation for the displacement an object travels from the starting point until it reaches a given velocity can be derived from the equations t = (v − vi)/g and y = gt2/2 + vit. This leads to the equation for the velocity when the object reaches a given displacement from the starting point.

The derived equations are:

y = (v2 − vi2)/2g

v = ±√(2gy + vi2)


Be observant and curious


Resources and references

Ron Kurtus' Credentials

Websites

Gravity Resources

Falling Bodies - Physics Hypertextbook

Equations for a falling body - Wikipedia

Gravity Calculations - Earth - Calculator

Books

Top-rated books on Simple Gravity Science

Top-rated books on Advanced Gravity Physics


Questions and comments

Do you have any questions, comments, or opinions on this subject? If so, send an email with your feedback. I will try to get back to you as soon as possible.


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