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Feedback Comments on Gravity
by Ron Kurtus
A total of 81 comments and questions have been sent in on Gravity. They are listed according to date.
You can read them to further your understanding of the subject.
List of most recent 10 letters
Topic |
Title |
Country |
| Convention for Direction in Gravity Equations | Velocity equations | India |
| Derivation of Velocity-Time Gravity Equations | Time to reach the ground | India |
| Mass and Weight Confusion | Clarifying confusion | USA |
| Artificial Gravity | Problem with spinning spaceship | USA |
| Center of Gravity | Center of gravity when standing on a ball | UK |
| Work Against Gravity | Would the Gravity book be helpful? | USA |
| Horizontal Motion Unaffected by Gravity | Finding the horizontal velocity | USA |
| Artificial Gravity | Idea to use Lenz"s Law for artificial gravity | Peru |
| Velocity Equations for Objects Projected Downward | Is the number in the equation squared? | Kenya |
| Velocity Equations for Objects Projected Upward | Projection at a 45 degree angle | USA |
Velocity equations
Topic: Convention for Direction in Gravity Equations
Question
June 17, 2019
Would you please Explain the sign convention of g with the following examples
A)A ball thrown vertically upwards from the ground.
B)A ball thrown vertically upwards from a tower of hight h.
Find the maximum hight, find the time of flight and also velocity of ball before it reaches the ground.
S - India
29073
Answer
The acceleration due to gravity (g) is positive toward the ground. When an object is thrown upwards, the force of gravity slows the velocity of the object.
See Gravity Equations for Objects Projected Upward..
To find the maximum height, you need the initial velocity upwards of the object, as well as the height from which it is thrown. The same is true for the time in flight.
Also see: Equations for Objects Projected Upward
Time to reach the ground
Topic: Derivation of Velocity-Time Gravity Equations
Question
January 27, 2019
I have seen an equation to calculate time of an object to reach the ground as
t=?2h/g
Can you please help understand how this equation has come
Srinivasan - India
28924
Answer
The time it takes a falling object to reach the ground is t = SQRT(2h/g) where h is the height or distance to the ground.
See Gravity Time Equations for Falling Objects for information.
I hope that helps.
Clarifying confusion
Topic: Mass and Weight Confusion
Question
February 28, 2018
I found this page in Google search and I would like to state that I believe you are incorrect in your assertion that pounds measure weight (or more accurately: force). You state confidently that "as a student of science, you need to be careful in what you call things." I do not believe you are being very careful when you state that pounds refers to weight. Pounds has always referred to mass (even if the unaware conflate that with weight, as you have done here).
Because weight is defined in relation to the gravitational constant, the side effect of this is that most of the time it works out and that is in fact why this mistake is so pervasive.
The correct terminology to use is pounds (or pounds-mass if you are being overly verbose) when referring to mass and pounds-force when referring to weight. This is codified by law and numerous standards. See NIST and the US Code for more information. The pound is defined as a direct ratio to kilograms. The transitive property applies here in an almost comically textbook way. Kilograms are a measure mass, pounds are defined in direct relation as a ratio to kilograms; thus pounds are a measurement of mass. There can be *no* other interpretation here.
Richard - USA
28461
Answer
Thanks for the comments. I updated Confusion about Mass and Weight Units to clarify the material.
Although some standards refer to pounds as mass, I found the definition of pounds as weight in five college Physics textbooks.
Also, weight refers to the force of gravity and not the gravitational constant. Although the mass is the same, the weight of an object on the Moon is only 1/6 the weight on Earth.
Problem with spinning spaceship
Topic: Artificial Gravity
Question
October 11, 2017
I can see a big problem where a spaceship has a spinning part as spaceship tries to make a turn. The spinning part want to go straight unfortunately the spaceship part wants to turn. It may be too much for the air seals.
a p - USA
28280
Answer
If a spaceship was a rotating wheel or had part of it rotating, and it made a turn to change directions, it would affect the artificial gravity inside the wheel. It could be possible for one side to increase the artificial gravity, while another part lose the gravity, such that people on that dies would start floating.
The best thing for a rotating spaceship would be to stay in a straight line or be in orbit around the Earth.
Air seals would not be a factor.
Center of gravity when standing on a ball
Topic: Center of Gravity
Question
September 20, 2017
If we are standing upright on the ball of one foot where would our centre of gravity be on our foot?
Athos - UK
28251
Answer
The centre of gravity would be somewhere in the centre of the person. However, there would be a ling going from the COG to the point where the foot meets the ball.
Would the Gravity book be helpful?
Topic: Work Against Gravity
Question
September 1, 2017
Hi, I will be working on a physics project this fall semester and was wondering if your book would be helpful in assisting with the project and/or project ideas.
Thank you,
Ashley - USA
28207
Answer
The advantage of the book is that everything is in one place, such that it is easier to navigate. However, all the material on Gravity and Gravitation is on the website. You can pick and choose what you want to see.
Best wishes for success in your Physics project.
Finding the horizontal velocity
Topic: Horizontal Motion Unaffected by Gravity
Question
January 11, 2016
Is there a way to find an objects horizontal velocity of a falling projectile using conservation of momentum, given the mass of the object, distance traveled and original height? If there is could you explain how to use such an equation?
Thank you
- USA
26682
Answer
The equation for the horizontal velocity as a function of mass, height, and distance traveled is v = x/SQRT(2y/g) where
v is the velocity
x is the distance traveled
y is the height
g is the acceleration due to gravity
SQRT is the square root sign.
See Effect of Gravity on Sideways Motion for details.
Idea to use Lenz"s Law for artificial gravity
Topic: Artificial Gravity
Question
December 15, 2015
If An astronaut use a magnetic suit within a copper's chamber, He needs to do a job for displacement due lenz's law. Read more:
Artificial gravity by lenz's effect
jorge - Peru
26630
Answer
According to Lenz's Law, a moving magnet in a copper chamber will experience a resistance to that movement, due to the electric fields produced. That means that an astronaut in a magnetic suit would experience resistance to his movement in a copper chamber.
Artificial gravity would be a force pulling him toward the floor, whether he moved or not. Thus, I don't think Lenz's Law would apply.
Is the number in the equation squared?
Topic: Velocity Equations for Objects Projected Downward
Question
December 15, 2015
from the equation v=±?[2gy+vi2],is it vi squared or vi multiplied by 2?
patrick - Kenya
26626
Answer
When the number is behind the variable (vi) and is above it, that means the variable is squared. Another way of writing vi squared is vi^2.
Projection at a 45 degree angle
Topic: Velocity Equations for Objects Projected Upward
Question
November 17, 2015
What if you were throwing at a 45 degree angle ? What's equation would be.
Fuad - USA
26542
Answer
See Effect of Gravity on an Artillery Projectile to see the equation at various angles.
Summary
Hopefully, this reader feedback has helped provide information about Gravity issues.
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